uitkomst:E_{\text{f}}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{}=1{,}8892\,(\text{eV})E_{f}=1{,}8892\,(\text{eV})E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,()E_{f}=1{,}8892\,(e)E_{f}=1{,}8892\,(eV)E_{f}=1{,}8892(eV)E_{f}=1{,}8892(eV)$E_{\mathrm{f}}=1{,}8892(\mathrm{eV})
voorbeeld van een antwoord:
•Er geldt:E_{\text{f}}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}E_{}=\frac{h c}{\lambda}$E_{\mathrm{f}}=\frac{h c}{\lambda}
Invullen levertE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~\text{J}E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~E_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3{,}02682\cdot10^{-19}~JE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=302682\cdot10^{-19}~JE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656{,}28\cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{65628\cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2{,}99792\cdot10^8}{656,28\cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot299792\cdot10^8}{656,28\cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{\text{f}}=\frac{6{,}62607\cdot10^{-34}\cdot2,99792\cdot10^8}{656,28\cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{\text{f}}=\frac{662607\cdot10^{-34}\cdot2,99792\cdot10^8}{656,28\cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{\text{f}}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~JE_{f}=\frac{6,62607 \cdot10^{-34} \cdot2,99792 \cdot10^{8}}{656,28 \cdot10^{-9}}=3,02682\cdot10^{-19}~J\text { Invullen levert } E_{\mathrm{f}}=\frac{6,62607 \cdot 10^{-34} \cdot 2,99792 \cdot 10^{8}}{656,28 \cdot 10^{-9}}=3,02682 \cdot 10^{-19} \mathrm{~J}
Omrekenen naar eV geeft:E_{\text{f}}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1{,}8892\text{ eV}E_{\text{f}}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=18892\text{ eV}E_{\text{f}}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{f}=\frac{3{,}02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{f}=\frac{302682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{f}=\frac{3,02682\cdot10^{-19}}{1{,}60218\cdot10^{-19}}=1,8892\text{ eV}E_{f}=\frac{3,02682\cdot10^{-19}}{160218\cdot10^{-19}}=1,8892\text{ eV}E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892\text{ eV}E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892E_{f}=\frac{3,02682 \cdot10^{-19}}{1,60218 \cdot10^{-19}}=1,8892eE_{\mathrm{f}}=\frac{3,02682 \cdot 10^{-19}}{1,60218 \cdot 10^{-19}}=1,8892 \mathrm{eV}
•Voor de energieniveaus van het waterstofatoom geldtE_{n}=-\frac{13{,}6\text{ eV}}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6}{n^2}E_{n}=-\frac{13{,}6e}{n^2}$E_{n}=-\frac{13{,}6 \mathrm{eV}}{n^{2}}.
Het eerste aangeslagen niveau is$n=2en het tweede is$n=3, dus voor de energie van de overgang geldt:\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\text{ eV}\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89e\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89e\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6\text{ eV}=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6e=1{,}89eV\left|E_{2\rightarrow3}\right|=\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)\cdot13{,}6eV=1{,}89eV\left|E_{2\rightarrow3}\right|=\frac{1}{2^{2}}-\frac{1}{3^{2}})\cdot13{,}6eV=1{,}89eV$\left|E_{2 \rightarrow 3}\right|=(\frac{1}{2^{2}}-\frac{1}{3^{2}}) \cdot 13{,}6 \mathrm{eV}=1{,}89 \mathrm{eV}.
(Deze energie is gelijk aan de fotonenergie van de656{,}28~\text{nm}-\text{lijn}656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-656{,}28~\text{nm}-e656{,}28~\text{nm}-eV656{,}28~\text{nm}-656{,}28~\text{nm}-l656{,}28~\text{nm}-li656{,}28~\text{nm}-lij656{,}28~\text{nm}-lijn656{,}28~\text{nm eV}-lijn656{,}28~\text{nm eV}-lijn656{,}28~\text{nm}-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~-lijn656{,}28~n-lijn$656{,}28 \mathrm{~nm}-\mathrm{lijn}.)
•(Het gaat om een emissielijn, dus) de overgang is van de tweede aangeslagen toestand naar de eerste.
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
Opmerking
Als de kandidaat voor het omrekenen van J naar eV gebruikmaakt van ScienceData tabel 1.3 is het juiste aantal significante cijfers twee.
