voorbeeld van een juist antwoord:
De verbruikte energie na 30 dagen is0{,}30\text{ kWh }/\,E=0{,}30\text{ kWh}0{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}300{,}30\text{ kWh }/\,E=0{,}30kWh0{,}30\text{ kWh }/E=0{,}30kWh0{,}30\text{ kWh }/E=0{,}30kWh0{,}30\text{ kWh }/E=0{,}30kWh0{,}30\text{ kWh }/E=0{,}30kWh0{,}30\text{ kWh}/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh0{,}30/E=0{,}30kWh$0{,}30 \mathrm{kWh} / E=0{,}30 \mathrm{kWh}. Dit is minder dan de helft van de opgeslagen energie in de accu.
Conclusie: Na een maand kan de camper nog wel gestart worden.
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
➤ Indien correct 1 punt:
Opmerking
Als de kandidaat eerst de opgeslagen energie in J uitrekent en daarna hoe lang het lampje daarmee kan branden, dit goed rekenen.