Teken in de afbeelding op de uitwerkbijlage de stuwkracht op topsnelheid vanuit punt P. Gebruik als krachtenschaal1{,}0~\text{cm}\,\widehat{=}\,5{,}0~\text{N}1{,}0~c\text{cm}\,\widehat{=}\,5{,}0~\text{N}1{,}0~c\text{Ncm}\,\widehat{=}\,5{,}0~\text{N}1{,}0~c\text{Nc}\,\widehat{=}\,5{,}0~\text{N}1{,}0~c\text{N}\,\widehat{=}\,5{,}0~\text{N}1{,}0~c,\text{N}\,\widehat{=}\,5{,}0~\text{N}1{,}0~c\text{N}\,\widehat{=}\,5{,}0~\text{N}1{,}0~\text{N}\,\widehat{=}\,5{,}0~\text{N}1{,}0~\,\widehat{=}\,5{,}0~\text{N}1{,}0~c\,\widehat{=}\,5{,}0~\text{N}1{,}0~cm\,\widehat{=}\,5{,}0~\text{N}1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~1{,}0~cm\,\widehat{=}\,5{,}0~N1{,}0~cm\,\widehat{=}5{,}0~N1{,}0~cm\,\widehat{=}5{,}0~N1{,}0~cm\,\widehat{=}5{,}0~N1{,}0~cm\widehat{=}5{,}0~N1{,}0~cm\widehat{=}5{,}0~N1{,}0~cm\widehat{=}5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm\hat{=}5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N1{,}0~cm5{,}0~N$1{,}0 \mathrm{~cm} \triangleq 5{,}0 \mathrm{~N}.